Group VII elements
Atomic Radii
Trends in atomic radii
Reason
Electronegativity
Units
Trends
Reason
Melting point and boiling points
Question: Why F2 is a gas and I2 is solid?
Reason
Melting point and boiling point
Melting and boiling points of halogens increases down the group because instantaneous dipole-induced dipole forces (Vender Wall forces) becomes stronger due to increase in atomic size and mass and hence size is small for F2 large for I2 . Therefore, F2 is a gas and Iodine is solid.
Bond enthalpy
Amount of energy required to break one mole of covalent bond to produce an individual atom is called bond enthalpy.
Cl-Cl -------------- > 2Cl- + Bond enthalpy
Question: Why bond theory of F2 is low as compared to the other group elements?
Answer
Reason: This is due to the fact that atomic size of chlorine very small and have two molecules so repulsion between non burning electron as well as between two nuclei is very high. This makes F-F bond very weak and helps in breaking F-F bond into F atoms. That's why bond bond enthalpy of F2 is very low.
Strength of halogens as oxidizing agent
Halogens have very high oxidizing power due to the high electronegativity (a tendency to attract a shared pair of electrons). The oxidizing property of halogen can be represented by:
½ X2 + e- ----------- > X- + energy
As electron affinity of halogen decreases down the group, oxidizing power also decreases. It decreases in following order.
F2 > Cl2 > Br2 > I2
Examples
F2 + 2Cl- ---------> 2F- + Cl2
F2 + 2NaCl --------- > NaF + Cl2
Br2 + 2I- ------------> 2Br- + I2
Acidity of hydrogen halide
Question: Why HF is a vehicle is said among other hydrogen halide?
HF <HCl < HBr < HI
Reason all the FS highly electronegative than other halogen but HF with the vehicle asset this is due to the following reason
I. HF makes hydrogen bonding so it doesn't release hydrogen easily so it is a weaker.
II. HF has high Bond enthalpy as compared to other halogen halide due to small size of fluorine atom.
III. Can't you get bases of HF is very strong so it is its acids week.
Halide and as reducing agent
Redox reaction of allied and with concentrated sulphuric acid
Cl- dil H2SO4 ---------- > Na2SO4 + 2HCl
ii. Bromide ion
NaBr + Conc. H2SO4 –---------- > Na2SO4 + HBr
HBr + H2SO4 ------- > Br2 + SO2 + H2O
iii. Iodine
NaI + Conc. H2SO4---- > Na2SO4 + HI
HI + H2SO4 ------- > I2 + H2S + 4H2S + 4H2O
Trends.
Reducing power of halide ions increases in following order.
F- < Cl- < Br- < I-
Reducing power of halide ions increases down the group.
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